Theoretical Calculation of Proton Radius

A single proton is almost non-radiating. It can be considered that a proton is a black hole in the microscopic world, and the densities of macroscopic black holes and microscopic black holes should be equal. My theory calculates that the density of black holes is constant, and the density of black holes is proportional to the cube of the speed of light. According to the theory that stars evolve into black holes, it can be deduced that the proportionality constant is: the density of the sun is: K=1.76×10^-7. Let's calculate the density of the black hole again, and substitute ρ=KC³==1.76×10^-7×(3×10⁸)³=4.752×10¹⁸(kg/m³), so the density of any black hole is 4.752×10¹⁸(kg /m³). The density of protons should be: 4.752 × 10¹⁸ (kg/m³). We know that the mass of the proton is 1.67×10^-27kg, we think that the proton is a sphere, ρ=M/V=M/(4/3)πR³, R³=M/ρ(4/3)π=1.67 ×10^-27/4.752×10¹⁸(4/3) π=0.84×10^-46(m), so R=0.44×10^-15(m), that is, the radius of the proton is theoretically estimated to be 0.44×10^-15(m) , This calculation is quite close to the experimental value of scientists.