The functional relationship between the ratio of the wavelength of light quantum and the radius of light quantum

The distance between the centers of two photons is the wavelength of the photons. One of the light quantum conclusions I introduced: Q=M^2R=1.83×10^-78——(1), where R is the radius of the photon, M is the mass of the photon, and the Q constant. The second conclusion of light quantum: mλ=H——(2), where m is the mass of the photon, λ is the wavelength of this type of photon, H is a constant, H=h/c=2.21×10^-42. Simultaneously (1) and (2) are solved: δ=λ/ R=HM/Q——(3), that is, the ratio of the wavelength of the photon to the radius of the photon is a proportional function, and it is an increasing function——and the photon is proportional to the quality. That is to say, the greater the mass of the light quantum, the greater the relative distance between the light quantum (the more open the two light quantum is), the smaller the wavelength, the less obvious the wave property, that is, the more obvious the particle property, and vice versa. We are calculating the proportionality constant of the δ(m) function, H/Q=2.21×10^-42/1.83×10^-78=1.21×10^36, we can see that the ratio of the wavelength of the light quantum to the radius is a proportional function, And the proportionality constant (slope) is large.