New explanation of Hubble's redshift

``Like mass attract, like energy repel each other.'' So the energy can make a repulsive gravity and a negative curvature. There is a balance of a flat universe between a gravity and a repulsive gravity. (1) $\Omega_m=\Omega_d=\Omega_g=\Omega_{rg}=0.5.$ Among it, $\Omega_m$: the density of matter, $\Omega_d$: the density of dark energy, $\Omega_g$: the density of matter of gravity, $\Omega_{rg}$: the density of matter of repulsive gravity. When the wave travel in the universe, its quantum space-time will conversion to an universal space-time. It will cause the quantum space-time to change. According to the Hubble's redshift, (2)$H_0\approx(\frac{\lambda}{D})\Delta\nu$. Among it, $H_0$: Hubble constant, $\nu$: the frequence, $\lambda$: the wavelength, D: the universal displacement, $\frac{\lambda}{D}$: the rate of the translation between the quantum space-time and the universal space-time. ``An energy momentum tensor scalar field is a space-time field. The quantum time is the frequance and the quantum space is the amplitude square.'' (see Dayong Cao, ``MEST,'' BAPS.2011.DFD.LA.25, ``MEST,'' BAPS.2010.DFD.QE.2, ``MEST,'' BAPS.2012.MAR.K1.256, ``MEST,'' BAPS.2012.APR.E1.2 and ``MEST,'' BAPS.2010.MAR.S1.240) So the universe do not expanding. Supported by AEEA.